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an ionized calcium atom has a charge of 2 elementary charges. if this ion is accelerated through a potential difference of 2.0 x 10^3 volts, the ion's change in kinetic energy will be

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Lanuel

The ion's change in kinetic energy will be [tex]4.0 \times 10^3\;eV[/tex]

Given the following data:

Charge = 2 Coulombs.

Potential difference = [tex]2.0 \times 10^3 \;Volts[/tex]

How to calculate the ion's change in kinetic energy.

Mathematically, kinetic energy of a charge is given by this formula:

[tex]K.E = qV[/tex]

Where:

  • K.E is the kinetic energy.
  • q is the charge.
  • V is the potential difference.

Substituting the given parameters into the formula, we have;

[tex]K.E = 2 \times 2.0 \times 10^3 \\\\K.E = 4.0 \times 10^3\;eV[/tex]

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