What is the length of BC to the nearest tenth?

The length of BC to the nearest tenth will be 20.7 units
The steps are as follow:
AC=B=15
AB=C=13
BC=A=?
Cos95° = (b^2+c^2-a^2)/2bc
Cos95° = (15^2+13^2-a^2)/(2*15*13)
2*13*15*cos 95 =15^2+13^2-a^2
-34=225+169-a^2
A^2=394+34
A^2=428
A = 20.68 = 20.7 units
So the length of BC to the nearest tenth will be 20.7 units
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