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A 6M sulfuric acid solution (H2SO4 in water) is flowing into a tank at the rate of 100 liters/min (also can be written 100 L/min). The density of the solution is 1.34 g/cm3 . Determine the value of the items requested below (show your work). For parts (b) - (d), first write out the equation using symbols for the appropriate variables, then algebraically solve for the unknown variables, and finally substitute in the numerical values and calculate the values for the unknown variables

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mickymike92

Based on the flow rate data provided for the 6 M sulfuric acid solution;

  • molar flow rate = 600 mol/min
  • Mass flow rate = 58.8 kg/min
  • total mass flow rate = 134 kg/min

What is the molar mass of sulfuric acid, H2SO4?

The molar mass of sulfuric acid is obtained from the molar atomic masses of it component elements.

Molar mass of H2SO4 = (2 × 1) + (32 × 1) + (16 × 4)

Molar mass of H2SO4 = (2 = 98 g/mol

Based on the flow rate data provided:

Moles of 6 M sulfuric acid in 100 L = molarity × volume

Moles of 6 M sulfuric acid in 100 L = 6 M × 100 L = 600 moles

molar flow rate = 600 mol/min

Mass of 600 moles sulfuric acid = moles × molar mass

Mass of 600 moles sulfuric acid = 600 × 98 = 58.8 kg

Mass flow rate = 58.8 kg/min

Mass of sulfuric acid in 100 L solution = volume × density

density of sulfuric acid = 1.34 g/cm^3 = 1.34 kg/L

Mass of sulfuric acid in 100 L solution = 1.34 kg/L × 100 L = 134 kg

Therefore, total mass flow rate = 134 kg/min

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