js229104
contestada

Consider functions f and g
f(x)=(1=2)^×+1 g(x)= log(x - 1) +1 Using three iterations of successive approximation, what is the approximate solution where f(x) g(x)? Use the graph as a starting point.​

Consider functions f and g fx121 gx logx 1 1 Using three iterations of successive approximation what is the approximate solution where fx gx Use the graph as a class=

Respuesta :

Answer:

x=39/16

Step-by-step explanation:

I looked it up. Here's the source's explanation;
[tex]f(x)=(1/2)^x+1[/tex]
[tex]g(x)=log(x-1)+1[/tex]

[tex]f(x)=g(x)[/tex]
[tex](1/2)^x +1=log(x-1)+1[/tex]
[tex](1/2)^x=log(x-1)[/tex]
2^(-x)=log (x-1)
x=2.5018
x=39/16

Otras preguntas