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Determine the empirical formula for :aluminum compound containing oxygen (alxoy) if 4.78g of al reacts and the total mass after reacting is 6.67g,

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samueladesida43

The empirical formula for a aluminum compound containing oxygen (AlxOy), if 4.78g of Al reacts is Al3O2.

How to calculate empirical formula?

According to this question, 4.78g of Al reacts with oxygen to form a total mass of 6.67g. This means that the mass of oxygen that reacted is 6.67 - 4.78 = 1.89g

  • Aluminum = 4.78g
  • Oxygen = 1.89g

First, we convert each mass to moles

  • Al = 4.78 ÷ 27g/mol = 0.17mol
  • O = 1.89 ÷ 16g/mol = 0.12mol

Next, we divide each value by the smallest

  • Al = 0.17 ÷ 0.12 = 1.42
  • O = 0.12 ÷ 0.12 = 1

Multiply each value by 2

Al = 2.8 = 3

O = 2

Therefore, the empirical formula for a aluminum compound containing oxygen (AlxOy), if 4.78g of Al reacts is Al3O2.

Learn more about empirical formula at: https://brainly.com/question/11588623

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