For a steel piano wire, 0.721 m long has a cross-sectional area of 0.00633 cm2. is mathematically given as
de=9.624723*10^{-4}m
What is the length of the wire stretch ?
Generally, the equation for the Hooks law is mathematically given as
F/A=Yde/e
Therefore
dl=fe/Ay
de=\frac{169*0.721}{0.00633*10^{-4}*2 x 10^{11} }
de=9.624723*10^{-4}
In conclusion, the wire stretch
de=9.624723*10^{-4}m
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