Option C) 19.3L is the correct answer.
Hence, the final volume of the gas at the standard atmospheres and temperature is 19.3L.
Given the data in the question;
- Initial volume of gas; [tex]V_1 = 29.3L[/tex]
At Standard temperature and pressure( STP)
- Initial temperature; [tex]T_1 = 273.15K[/tex]
- Initial pressure; [tex]P_1 = 1.00atm[/tex]
Then
- Final pressure; [tex]P_2 = 1.39atm[/tex]
- Final temperature; [tex]T_2 = -23.0^0C = 250.15K[/tex]
Final Volume; [tex]V_2 = \ ?[/tex]
Combined gas law
Combined gas law combines both Boyle's Law, Charles's Law, and Gay-Lussac's Law. It states that the ratio of the product of volume and pressure and the absolute temperature of a gas is equal to a constant.
It is expressed as;
[tex]\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}[/tex]
To determine the new volume of the gas, we substitute our values into the expression above.
[tex]\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}\\\\P_1V_1T_2 = P_2V_2T_1\\\\1.00atm * 29.3L * 250.15K = 1.39atm * V_2 * 273.15K\\\\7329.395atm.L.K = 379.6785atm.K * V_2\\\\V_2 = \frac{7329.395atm.L.K}{379.6785atm.K} \\\\V_2 = 19.3L[/tex]
Option C) 19.3L is the correct answer.
Hence, the final volume of the gas at the standard atmospheres and temperature is
Learn more about the combined gas law: https://brainly.com/question/25944795
