From the given coordinates of point A(4, 0), and D (-4, 0), the area of the hexagon is 33.94 units square.
How can the area of the hexagon be found?
The given parameters are;
Shape of the quilt pattern = A regular hexagon
Coordinates of point A = A(4, 0)
Coordinates of point D = D(-4, 0)
Required;
The area of the hexagon
Solution;
The coordinates of the center of the hexagon, P = (0, 0)
A regular hexagon consist of six equilateral triangles.
The length of a side of the triangle = PA
Length of PA = 4 - 0 = 4
Therefore;
Length of a side of the triangle = 4
Height of the triangle = PA × sin(60)
Which gives;
Height of the triangle = 4 × (√3)/2 = 2•√3
Area of one triangle = (4 ÷ 2) × 2•√3 = 4•√2
Area of the 6 triangles is therefore;
A = 6 × 4•√2 = 24•√2
Area of the 6 triangles = Area of the hexagon
Therefore;
- Area of the hexagon = 24•√2 = 33.94 square units.
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