50 POINTS FOR CORRECT AWNSER

Answer:
[tex]y\leq \frac{1}{2} x+3[/tex]
Step-by-step explanation:
slope intercept form is [tex]y=mx+b[/tex] where [tex]m[/tex] is the gradient and [tex]b[/tex] is the y-intercept (the number at which it crosses the y axis)
firstly find the equation for this line:
the gradient can be found with the formula [tex]\frac{y_{2} -y_{1} }{x_{2} -x_{1} }[/tex]
so the gradient is [tex]\frac{4-3}{2-0}=\frac{1}{2} =0.5[/tex]
the y intercept is where it crosses the y axis so it is simply 3
our equation for the line is now [tex]y=\frac{1}{2} x+3[/tex] but the question is asking for an equality where the shaded area is BELOW the line.
so the inequality is [tex]y\leq \frac{1}{2} x+3[/tex]
Answer:
y ≤ [tex]\frac{1}{2}[/tex] x + 3
Step-by-step explanation:
the equation of the line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
calculate m using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = (- 6, 0) and (x₂, y₂ ) = (0, 3) ← 2 points on the line
m = [tex]\frac{3-0}{0-(-6)}[/tex] = [tex]\frac{3}{0+6}[/tex] = [tex]\frac{3}{6}[/tex] = [tex]\frac{1}{2}[/tex]
the line crosses the y- axis at (0, 3 ) ⇒ c = 3
y = [tex]\frac{1}{2}[/tex] x + 3 ← is the equation of the line
the solution lies below the line and on the line.
as line is solid use ≤
y ≤ [tex]\frac{1}{2}[/tex] x + 3