Respuesta :

Answer:

[tex]y\leq \frac{1}{2} x+3[/tex]

Step-by-step explanation:

slope intercept form is [tex]y=mx+b[/tex] where [tex]m[/tex] is the gradient and [tex]b[/tex] is the y-intercept (the number at which it crosses the y axis)

firstly find the equation for this line:

the gradient can be found with the formula [tex]\frac{y_{2} -y_{1} }{x_{2} -x_{1} }[/tex]

so the gradient is [tex]\frac{4-3}{2-0}=\frac{1}{2} =0.5[/tex]

the y intercept is where it crosses the y axis so it is simply 3

our equation for the line is now [tex]y=\frac{1}{2} x+3[/tex] but the question is asking for an equality where the shaded area is BELOW the line.

so the inequality is [tex]y\leq \frac{1}{2} x+3[/tex]

Answer:

y ≤ [tex]\frac{1}{2}[/tex] x + 3

Step-by-step explanation:

the equation of the line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 6, 0) and (x₂, y₂ ) = (0, 3) ← 2 points on the line

m = [tex]\frac{3-0}{0-(-6)}[/tex] = [tex]\frac{3}{0+6}[/tex] = [tex]\frac{3}{6}[/tex] = [tex]\frac{1}{2}[/tex]

the line crosses the y- axis at (0, 3 ) ⇒ c = 3

y = [tex]\frac{1}{2}[/tex] x + 3 ← is the equation of the line

the solution lies below the line and on the line.

as line is solid use ≤

y ≤ [tex]\frac{1}{2}[/tex] x + 3