PLEASE HELP AND ANSWER CORRECTLY

I know the axis of symmetry but I don't know how to put it in an equation

please review the graph and answer you may use the other answers to help

PLEASE HELP AND ANSWER CORRECTLYI know the axis of symmetry but I dont know how to put it in an equationplease review the graph and answer you may use the other class=
PLEASE HELP AND ANSWER CORRECTLYI know the axis of symmetry but I dont know how to put it in an equationplease review the graph and answer you may use the other class=

Respuesta :

Answer:

standard form:   y = x² - 2x - 8

vertex form:  y = (x − 1)² - 9

factorized form:  y = (x + 2)(x - 4)

Step-by-step explanation:

From inspection of the graph:

  • Axis of symmetry:  x = 1
  • Vertex = (1, -9)
  • x-intercepts = (-2, 0) and (4, 0)
  • y-intercept = (0, -8)

Standard quadratic form:   y = ax² + b x + c

Vertex form of a quadratic equation:   y = a(x − h)² + k

If a > 0 then the parabola opens upwards

If a < 0 then the parabola opens downwards

(h, k) is the vertex

c is the y-intercept

Inputting the vertex into the vertex form gives:

y = a(x − 1)² - 9

  = a(x² - 2x + 1) - 9

  = ax² - 2ax - 8

Using the x-intercepts to create a quadratic equation:

y = a(x + 2)(x - 4)

  = a(x² - 2x - 8)

  = ax² - 2ax - 8a

Comparing the y-intercepts:

-8 = -8a  ⇒  a = 1

Therefore,   y = x² - 2x - 8