Dividing 6x^2 + 26x^2 + 23x + 5 by 3x + 1 using the long division involves the use of groups or parts
The result when 6x^2 + 26x^2 + 23x + 5 is divided by 3x + 1 is 2x^2 + 8x + 5 with no remainder
How to carry out the long division?
The dividend is given as:
6x^2 + 26x^2 + 23x + 5
And the divisor is 3x + 1
Divide 6x^3 by 3x:
Result = 2x^2
Multiply 2x^2 by 3x + 1
=> 6x^3 + 2x^2
Subtract 6x^3 + 2x^2 from 6x^3 + 26x^2 + 23x + 5
=> 24x^2 + 23x + 5
Divide 24x^2 by 3x:
Result = 8x
Multiply 8x by 3x + 1
=> 24x^2 + 8x
Subtract 24x^2 + 8x from 24x^2 + 23x + 5
=> 15x + 5
Divide 15x by 3x:
Result = 5
Multiply 5 by 3x + 1
=> 15x + 5
Subtract 15x + 5 from 15x + 5
=> 0
Write out the sum of the results
Result = 2x^2 + 8x + 5
Hence, the result when 6x^2 + 26x^2 + 23x + 5 is divided by 3x + 1 is 2x^2 + 8x + 5 with no remainder
See attachment for the long division process
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