This week you practice your instrument for 3 1/4 on Monday, 2 1/2 hours on Tuesday and 1 hour on Wednesday. Next week you practice for the same number of hours. What is the total number of hours you will have practiced over these six days?
Which expression correctly shows how to solve this problem?

A. 3 1/4 + 2 1/2 + 1
B. (3 1/4 + 2 1/2) + (3 1/4 + 2 1/2)
C. (3 1/4 + 2 1/2 + 1) + (3 1/4 + 2 1/2+ 1


Thank You so much!!!!

This week you practice your instrument for 3 14 on Monday 2 12 hours on Tuesday and 1 hour on Wednesday Next week you practice for the same number of hours What class=

Respuesta :

Lenvy

Answer:

C. (3 1/4 + 2 1/2 + 1) + (3 1/4 + 2 1/2+ 1)

Step-by-step explanation:

Since, this week you practice your instrument for 3 1/4 on Monday, 2 1/2 hours on Tuesday and 1 hour on Wednesday.

And, next week you practice for the same number of hours.

Same number = (3 1/4 + 2 1/2 + 1)

Thus, [C] (3 1/4 + 2 1/2 + 1) + (3 1/4 + 2 1/2+ 1) is correct.

~Lenvy~

Answer:

[C} [tex]\left(3\frac{1}{4}+2\frac{1}{2}+1\right)+\left(3\frac{1}{4}+2\frac{1}{2}+1\right)[/tex]

Step-by-step explanation:

Given:

this week you practice your instrument for 3 1/4 on Monday, 2 1/2 hours on Tuesday and 1 hour on Wednesday.

Next week you practice for the same number of hours.

To Find:

What is the total number of hours you will have practiced over these six days?

Which expression correctly shows how to solve this problem

Solve:

Knowing that you practice for 3 1/4 on Monday, 2 1/2 hours on Tuesday and 1 hour on Wednesday. Next week you practice the same. Thus, we can know that [C} [tex]\left(3\frac{1}{4}+2\frac{1}{2}+1\right)+\left(3\frac{1}{4}+2\frac{1}{2}+1\right)[/tex] is the correct answer.

Solution if needed.

[tex]\left(3\frac{1}{4}+2\frac{1}{2}+1\right)+\left(3\frac{1}{4}+2\frac{1}{2}+1\right)[/tex]

[tex]=\left(\frac{13}{4}+\frac{5}{2}+1\right)+\left(3\frac{1}{4}+2\frac{1}{2}+1\right)[/tex]

= [tex]\left(\frac{13}{4}+\frac{5}{2}+1\right)+\left(\frac{13}{4}+2\frac{1}{2}+1\right)[/tex]

[tex]=\left(\frac{13}{4}+\frac{5}{2}+1\right)+\left(\frac{13}{4}+\frac{5}{2}+1\right)[/tex]

[tex]\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}[/tex]

[tex]=\frac{27}{4}+\left(\frac{13}{4}+\frac{5}{2}+1\right)[/tex]

[tex]=\frac{27}{4}+\frac{27}{4}[/tex]

[tex]=\frac{27}{2}[/tex]

[tex]=13\frac{1}{2}[/tex]

Solution ⇒ [tex]=13\frac{1}{2}[/tex]

[RevyBreeze]