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With upward speeds of 12.5 m/s, the elevators in the Yokohama Landmark Tower in Yokohama, Japan, are among the fastest elevators in the world. Suppose a passenger with a mass of 70.0 kg enters one of these elevators. The elevator then goes up, reaching full speed in 4.00 s. Calculate the net force that is applied to the passenger during the elevator's acceleration.

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asuwafohjames

The net force that is applied to the passenger during the elevator acceleration is 218.75 N.

What is net force?

This is the single force obtained from the combinatiion of two or more forces

To calculate the net force that is applied to the passenger during the elevator's acceleration, we use the formula below.

Formula:

  • F = m(v-u)/t............ Equation 1

Where:

  • F = force
  • m = mass
  • v = Final velocity
  • u = initial velocity
  • t = time.

From the question,

Given:

  • m = 70 kg
  • u = 0 m/s
  • v = 12.5 m/s
  • t = 4 s

Substitute these values into equation 1

  • F = 70(12.5-0)/4
  • F = 218.75 N

Hence, The net force that is applied to the passenger during the elevator acceleration is 218.75 N.

Learn more about net force here: https://brainly.com/question/13370981

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