Trigonometry, how would I find the area of this triangle?

Answer:
Step-by-step explanation:
Area of triangle = 1/2 * base * height
Use the side of length 5.6cm as base, the height will be a perpendicular line from the base to the tip of the triangle.
From the right-angle triangle formed by the height and the side of length 3.9cm,
sin(56°45') = height / 3.9
height = 3.9*sin(56°45')
Substituting back into the area equation:
Area = 1/2*5.6*3.9*sin(56°45')
= 9.0cm^2
= 9cm^2
Use sine rule for Area
[tex]\\ \rm\rightarrowtail Area=\dfrac{1}{2}absinC[/tex]
[tex]\\ \rm\rightarrowtail Area=\dfrac{1}{2}(3.9)(5.6)sin56°45'[/tex]
[tex]\\ \rm\rightarrowtail Area=10.92(0.836)[/tex]
[tex]\\ \rm\rightarrowtail Area=10.22cm^2[/tex]