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Propane, C3H8, is a liquid in a pressurized barbecue tank but vaporizes instantly as it
flows out of the tank. Calculate the mass of propane that would vaporize as a result
of absorbing 100.0 kJ of energy. The molar enthalpy of vaporization of propane is
15.7 kJ/mol.

Respuesta :

Eduard22sly

The mass of propane, C₃H₈ that will vaporise as a result of absorbing 100 KJ of energy is 280.25 g

Data obtained from the question

  • Molar enthalpy of vaporization of propane = 15.7 KJ/mol
  • Energy = 100 KJ
  • Mass of propane =?

How to determine the mass of propane

1 mole of propane C₃H₈ = (3×12) + (1×8) = 44 g

From the question given above,

15.7 KJ of heat energy vaporised 44 g of propane.

Therefore,

100 KJ of heat energy will vaporise = (100 × 44) / 15.7 = 280.25 g of propane

Thus, 280.25 g of propane were vaporised from the tank.

Learn more enthalpy change:

https://brainly.com/question/11967318

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