Respuesta :

luana
[tex]4|4x-3|-8=-4\\\\ 4(4x-3)-8=-4\ \ \ \ or\ \ \ \ 4(-4x+3)-8=-4\\\\ 16x-12-8=-4\ \ \ or\ \ \ \ -16x+12-8=-4\\\\ 16x-20=-4\ \ \ \ or\ \ \ \ -16x+4=-4\\\\ 16x=16\ \ \ \ \ or\ \ \ \ -16x=-8\\\\ x=1\ \ \ \ or\ \ \ \ x=\frac{1}{2}[/tex]
konrad509
[tex] 4|4x-3|-8=-4\\ 4|4x-3|=4\\ |4x-3|=1\\ 4x-3=1 \vee 4x-3=-1\\ 4x=4 \vee 4x=2\\ x=1 \vee x=\dfrac{1}{2} [/tex]