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Listed below are the step equations for the reaction in which sulfur dioxide (SO2) and hydrogen disulfide (H2S) react to produce sulfur and water. Write the balanced target equation and use Hess’s law to calculate the ΔH of this reaction.

SO2 (g) → S (s) + O2 (g) ΔH = +300.1 kJ
H2 (g) + S (s) → H2S (g) ΔH = –19.5 kJ
H2 (g) + O2 (g) → H2O (g) ΔH = –290.1 kJ

Respuesta :

mickymike92

Based on Hess law, the enthalpy change, ΔH of the reaction is +48.9 kJ.

What is the equation of the reaction?

The equation of the reaction of sulfur dioxide (SO2) and hydrogen disulfide (H2S) to produce sulfur and water is given below:

[tex]SO_2 + 2H_2S \rightarrow 3S + 2H_2O[/tex]

The ΔH of the reaction is calculated from the summation of the ΔH of the intermediate reactions according to Hess law.

SO2 (g) → S (s) + O2 (g) ΔH1 = +300.1 kJ

H2 (g) + S (s) → H2S (g) ΔH2 = –19.5 kJ

2H2 (g) + O2 (g) → 2H2O (g) ΔH3 = –290.1 kJ

ΔH of the reaction = ΔH1 + 2(-ΔH2) + ΔH3

ΔH of the reaction = 300 + 2 × -(-19.5) + (-290.1)

ΔH of the reaction = +48.9 kJ

Therefore, the ΔH of the reaction is +48.9 kJ.

Learn more about Hess law at: https://brainly.com/question/9328637

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