contestada

A 250-turn generator with circular loops of radius 15 cm rotates at 60.0 rpm in a
magnetic field with a strength of 1.00 T.
a. What is the angular speed of the loops?
b. What is the area of one loop?
c. What is the maximum emf?
d. What is the rms emf?

Respuesta :

(a) The angular speed of the loops is 6.284 rad/s.

(b) The area of one loop is 0.071 m².

(c) The maximum emf of the generator is 111.54 V.

(d) The rms emf of the generator 78.87 V.

Angular speed of the loop

The angular speed of the loop is calculated as follows;

[tex]\omega = 60 \ \frac{rev}{\min} \times \frac{2\pi \ rad}{1 \ rev} \times \frac{1 \min}{60 \ s} \\\\\omega = 6.284 \ rad/s[/tex]

Area of the loop

The area of the loop is calculated as follows;

A = πr²

A = π x (0.15)²

A = 0.071 m²

Maximum emf of the generator

emf(max) = NBAω

emf(max) = (250) x (1) x (0.071) x (6.284)

emf(max) = 111.54 V

Rms emf of the generator

[tex]V_{rms} = \frac{V_0}{\sqrt{2} } \\\\V_{rms} = \frac{111.54}{\sqrt{2} } \\\\V_{rms} = 78.87 \ V[/tex]

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