Answer:
[tex]\implies m\angle A =42\degree[/tex]
Step-by-step explanation:
Quadrilateral ABCD is inscribed in circle with center O.
-> Quadrilateral ABCD is cyclic.
Opposite angles of a cyclic quadrilateral are supplementay.
[tex]\implies m\angle B + m\angle D = 180\degree[/tex]
[tex]\implies (2x)\degree + (3x-5)\degree = 180\degree[/tex]
[tex]\implies (5x-5)\degree = 180\degree[/tex]
[tex]\implies 5x-5= 180[/tex]
[tex]\implies 5x= 185[/tex]
[tex]\implies x= \frac{185}{5}[/tex]
[tex]\implies x= 37[/tex]
[tex]\implies m\angle A =(x+5)\degree[/tex]
[tex]\implies m\angle A =(37+5)\degree[/tex]
[tex]\implies \huge{\orange{m\angle A =\boxed{42}\degree}}[/tex]
