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samueladesida43

The specific heat capacity of Aluminum of mass 3 grams that was heated from 20 °C to 662 °C while absorbing 1728 J of heat is 12.5 J/g°C.

What is specific heat capacity?

The specific heat capacity of a substance can be calculated using the following formula:

Q = m × c × ∆T

Where;

  • Q = quantity of heat absorbed or released
  • m = mass of substance
  • c = specific heat capacity
  • ∆T = change in temperature

According to this question, 3 grams of Aluminum was heated from 20 °C to 66.2 °C while absorbing 1728 J of heat.

1728 = 3 × c × (66.2 - 20)

1728 = 138.6c

c = 1728 ÷ 138.6

c = 12.5 J/g°C

Therefore, the specific heat capacity of Aluminum of mass 3 grams that was heated from 20 °C to 662 °C while absorbing 1728 J of heat is 12.5 J/g°C.

Learn more about specific heat capacity at: https://brainly.com/question/1747943

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