We will see that there are 847,660,528 different ways in which the copies can be stored.
In how many ways can the 10 copies be stored?
So, we know that the copies can be stored in any of 40 computers, such that each computer can get, at most, one copy.
Then what we need to do is find how many different combinations of 10 computers can we make with the set of 40 computers, this is given by using the combination formula:
[tex]C(40, 10) = \frac{40!}{(40 - 10)!*10!} = \frac{40*39*38*37*36*35*34*33*32*31}{10*9*8*7*6*5*4*3*2} = 847,660,528[/tex]
This means that the 10 computes can be selected in 847,660,528 different ways, so there are 847,660,528 different ways in which the copies can be stored.
If you want to learn more about combinations, you can read:
https://brainly.com/question/11732255
