For a radioactive isotope has an activity of 9.60 mCi. , the half-life of the isotope is mathematically given as
t0.5 = 23893 s
What is the half-life of the isotope?
Generally, the equation for the half-life is mathematically given as
t0.5=T*0.693
Where
A = A0 e^(-t/T)
t/T = lnA0/A
3.75 hours/T=ln 9.60/7.39
T = 34478.5 s
Therefore
t1/2 = TX0.693
t0.5 = 23893 s
In conclusion, the half life
t0.5 = 23893 s
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