Answer:
D. the absolute deviation is 3
Step-by-step explanation:
Given:
- data = [7,10,10,14,14,17]
MAD:
[tex]\displaystyle \large{\dfrac{1}{n}\sum_{i=1}^{n}|x_i-m| = \dfrac{|x_1-m|+|x_2-m|+|x_3-m|+...+|x_n-m|}{n}}[/tex]
Therefore:
[tex]\displaystyle \large{MAD=\dfrac{|7-12|+|10-12|+|10-12|+|14-12|+|14-12|+|17-12|}{6}}\\\displaystyle \large{MAD=\dfrac{5+2+2+2+2+5}{6}}\\\displaystyle \large{MAD=\dfrac{18}{6}}\\\displaystyle \large{MAD = 3}[/tex]
Therefore, absolute deviation is 3
