Answer:
[tex]y-6=\frac{3}{2} (x+6)[/tex]
Step-by-step explanation:
Hi there!
We are given a point (-6, 6) and a slope of [tex]\frac{3}{2}[/tex]
We want to write the equation of the line that contains this point and slope in point-slope form
Point-slope form is written as [tex]y-y_1=m(x-x_1)[/tex], where m is the slope and [tex](x_1, y_1)[/tex] is a point
As we are already given everything we need, we can simply substitute the values into the formula
Starting with the slope, substitute 3/2 as m into the equation:
[tex]y-y_1=\frac{3}{2} (x-x_1)[/tex]
Now substitute -6 as [tex]x_1[/tex] and 6 as [tex]y_1[/tex]
[tex]y-6=\frac{3}{2} (x--6)[/tex]
Simplify:
[tex]y-6=\frac{3}{2} (x+6)[/tex]
Hope this helps!
