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A chemist reacted 17.25 grams of sodium metal with an excess amount of chlorine gas. The chemical reaction that occurred is shown.

Na + Cl2 → NaCl

If the percentage yield of the reaction is 88%, what is the actual yield? Show your work, including the use of stoichiometric calculations and conversion factors.

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Answer:

The actual yield is 38.59g of NaCl

Explanation:

Balanced equation: 2Na+CI2-->2NaCl

actual yield= (percent yield*theoretical yield)/100

Theoretical yield= 

17.25*(1/22.989769)*(2/2)*(58.442769)=43.8515

43.8515*0.88=38.59 grams of NaCl

The actual yield is 38.59g of NaCl

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