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If the astronaut throws the 3.20 kg tool with an acceleration of 5.90 m/s2 , what is the magnitude of the acceleration a of the astronaut during the throw

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onyebuchinnaji

The magnitude of the acceleration a of the astronaut during the throw of the 3.2 kg tool is determined as (18.88)/m.

Force applied to the tool

Based on Newton's third law of motion, the force applied to the tool by the atronaut is equal to the force exerted on the astronaut by the tool.

Fa = - Fb

where;

  • Fa is force exterted by the astronaut
  • Fb is force exterted by the tool

Fa = (3.2 x 5.9)

Fa = 18.88 N

Acceleration of the astronaut

Fa = m x a

where;

  • m is mass of the astronaut
  • a is the acceleration of the astronaut

a = Fa/m

a = (18.88)/m

Thus, the magnitude of the acceleration a of the astronaut during the throw of the 3.2 kg tool is determined as (18.88)/m.

Learn more about acceleration here: https://brainly.com/question/14344386

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