Anyone know where I can find the answers to this packet

Answer:
Step-by-step explanation:
I'll give you a guide — use the formula
[tex]y = mx + b[/tex]
For Question 1, [tex]y = \frac{2}{3}x + 2[/tex]
[tex]y = mx + b[/tex]
So, m = [tex]\frac{2}{3}[/tex] and b = 2
For question 3,
[tex]y = mx + b[/tex]
if m = [tex]\frac{1}{3}[/tex] and b = 3
[tex]y = \frac{1}{3}x + 3[/tex]
For the graphs, You label the center as 0, and go up/down 1 right to left and up down
You use every number on the x-axis (horizontal left-right line) and put it in your equation (e.g. [tex]y = \frac{2}{3}x + 2[/tex]) to get the value for the y-axis.