By the use of Ohm's law, the resistance of the bulb is 121 ohms
Let us recall that power is the rate of doing work. Now we know that the voltage of the power source is 110-V and the power is 100-W.
Since;
P= IV
I = P/V
I = 100/110
I = 0.91 A
Again;
V= IR
R = V/I
R = 110/0.91
R = 121 ohms
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