The magnitude of the force on the charge by the influence of the magnetic field will be 6.6*10^-3 N
Magnetic force, attraction or repulsion that arises between electrically charged particles because of their motion.The magnitude of the magnetic force acting on the charge is given by:
[tex]\rm F=qvBsin\theta[/tex]
where
The magnitude of the charge [tex]q=5.7\ \mu C =5.7\times 10^{-6} \ C[/tex]
The velocity of the charge [tex]v=4.5\times 10^5\ \frac{m}{s}[/tex]
The magnitude of the magnetic field [tex]3.2\ mT=0.0032\ T[/tex]
The angle between the directions of v and B [tex]\theta =90^o-37^o=53^o[/tex]
By substituting the values we will get:
[tex]F=(5.7\times 10^}-6})(4.5\times 10^5)(0.0032)(Sin53^o)[/tex]
[tex]F=6.6\times 10^{-3}\ N[/tex]
Hence the magnitude of the force on the charge by the influence of the magnetic field will be 6.6*10^-3 N
To know more about Magnetic force follow
https://brainly.com/question/14411049