At noon, ship A is 170 km west of ship B. Ship A is sailing east at 40 km/h and ship B is sailing north at 15 km/h. How fast (in km/hr) is the distance between the ships changing at 4:00 p.m.? (Round your answer to three decimal places.)

Respuesta :

Distance is the product of speed and time. The rate at which the distance between the ships changes at 4:00 p.m is 27.293 km/h.

What is the distance?

Distance is the product of speed and time. It is given by the function,

[tex]\rm Distance = Time \times speed[/tex]

Given at noon the distance between two ships is 170 km. Furter ship A is moving towards the east at a speed of 40 km/h, therefore, the distance covered by Ship A in 4 hours will be,

[tex]\rm \text{Distance covered by Ship A in 4 hours} = 4 \times 40 = 160\ km[/tex]

The distance covered by Ship B in 4 hours will be,

[tex]\rm \text{Distance covered by Ship B in 4 hours} = 4 \times 15= 60\ km[/tex]

At 4 pm the distance between the two ships is the hypotenuse of the red triangle as shown below,

[tex]\rm Hypotenuse = \sqrt{10^2 + 60^2} = \sqrt{100+3600 }= 60.827\ km[/tex]

The rate of change in the distance between the two ships can be written as,

[tex]\rm \text{Rate of change of distance} = \dfrac{170-60.827}{4} = 27.293\ km/h[/tex]

Hence, the rate at which the distance between the ships changes at 4:00 p.m is 27.293 km/h.

Learn more about Distance:

https://brainly.com/question/15100898

#SPJ1

Ver imagen ap8997154