Answer:
P(A|B) = 0.5
Step-by-step explanation:
A: set of prime numbers ={1,2,3}
B: set of divisors of 3 ={1,3}
P(A)=P(1)+P(2)+P(3)= 0.1+0.1+0.3 =0.5
P(B)=P(1)+P(3)=0.1+0.3=0.4
P(A|B) means: probability of A knowing that B
In other words we have to find the probability that a prime outcome occurs knowing that it is a divisor of 3
Its formula is given by:
P(A|B) = P(AintersectionB) /P(B)
A intersection B: outcome is prime and a divisor of 3 at the same time. (common elements between sets A and B)
A int B= {1,3}
P(AintB)= P(A)xP(B) = 0.5x0.4=0.2
Now back to the formula:
P(A|B) =P(AintB) / P(B)
=0.2/0.4=0.5
HOPE THIS HELPS :)
