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A gas has a temperature of 14 degrees C and a volume of 4.5 L. If the temp is raised to 29 degrees C and the pressure is not changed, what is the new volume of the gas

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adaujames25

Answer:

V1/T1 = V2/T2 (Charles' Law)

T is in Kelvin. Celsius temp plus 273.15 = K

T1 = 14 +273

= 287 K

T2 = 29 + 273

= 303 K

4.5 / 287 = V2 / 303

V2 = 4.75 L

= 4.8 L
Around 4.82 L. You solve using Charles Law which is p1/t1=p2/t2, u must transfer celsius to kelvin

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