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1) How many molecules of K2CrO4 are in 0.6 moles?

2) How many atoms of K are in 0.6 moles of K2CrO4?


3) You dilute 0.5 mol of NaOH to form 2 L of solution. What is the Molarity of that solution?

4) You dissolve 50 g of sugar to make 250 g of sugar water. What is the percent by mass?

5) A 2 L bottle of 5% vinegar has how much vinegar by volume?

Respuesta :

Eduard22sly

Given the various data from the question, the answers to each question is given below:

1. How to determine the number of molecules

Avogadro's hypothesis

1 mole of K₂CrO₄ = 6.02×10²³ molecules

Therefore,

0.6 mole of K₂CrO₄ = 0.6 × 6.02×10²³

0.6 mole of K₂CrO₄ = 3.612×10²³ molecules

2. How to determine the number of atoms

1 mole of K₂CrO₄ contains 2 moles of K.

Therefore,

0.6 mole of K₂CrO₄ will contain = 0.6 × 2 = 1.2 mole of K

From Avogadro's hypothesis,

1 mole of K = 6.02×10²³ atoms

Therefore,

1.2 mole of K = 1.2 × 6.02×10²³

1.2 mole of K = 7.224×10²³ atoms

Therefore, we can say that

0.6 mole of K₂CrO₄ = 7.224×10²³ atoms of K

3. How to determine the molarity

Molarity is defined as:

Molarity = mole / Volume

From the question given above, we obtained the following:

  • Mole = 0.5 mole
  • Volume = 2 L
  • Molarity =?

Molarity = mole / Volume

Molarity = 0.5 / 2

Molarity = 0.25 M

4. How to determine the volume

From the question given above, the following data were obtained:

  • Mass of solute = 50 g
  • Mass of solution = 250 g
  • Percentage of sugar =?

Percentage = (mass of solute / mass of solution) × 100

Percentage of sugar = (50 / 250) × 100

Percentage of sugar = 20%

5. How to determine the volume

Total volume = 2 L

Percentage of vinegar = 5%

Volume of vinegar =?

Volume = percent × total volume

Volume of vinegar = 5% × 2

Volume of vinegar = 0.1 L

Learn more about Avogadro's number:

https://brainly.com/question/26141731

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