contestada

Sonny is twice as old as Wale. Four years ago, he
was four times as old as Wale. When will the
sum of their ages be 66?

Respuesta :

Let S be Sonny age now and W be Wale age now

[tex]S=2W[/tex]

[tex]S-4=4(W-4)[/tex]

[tex]S-4=4W-16[/tex]

[tex]S=4W-16+4=4W-12[/tex] but [tex]S=2W[/tex]

[tex]2W=4W-12[/tex]

[tex]2W-4W=-12[/tex]

[tex]-2W=-12[/tex]

  • [tex]W=12[/tex] ÷ [tex]2=6[/tex] years old age of Wale now
  • [tex]S=2W=2(6)=12[/tex] years old age of Sonny now

When will the sum of their ages be 66? Let x be the number of years from now that the sum of their ages be 66, so Sonny will be [tex]12+x[/tex] and Wale will be [tex]6+x[/tex]:

  • [tex](12+x)+(6+x)=66[/tex]
  • [tex]18+2x=66[/tex]
  • [tex]2x=66-18=48[/tex]
  • [tex]x=48[/tex] ÷ [tex]2=24[/tex] years from now

Therefore, 24 years from now, Sonny will be [tex]12+24=36[/tex] years old and Wale will be [tex]6+24=30[/tex] years old and the sum of their ages will be [tex]36+30=66[/tex] years.

Learn more: https://brainly.com/question/1383487

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