need help with question 16

Answer:
C)
Step-by-step explanation:
u = x + 1
u - 1 = x
[tex]\int\limits {\dfrac{x}{\sqrt{x+1}}} \, dx = \int\limits {\dfrac{u-1}{\sqrt{u}}} \, du \\\\[/tex]
[tex]=\int {\left(\dfrac{u}{u^{\frac{1}{2}}}-\dfrac{1}{u^{\frac{1}{2}}} \right )\, du \\\\ = \int {u^{1-\frac{1}{2}}-1*u^{\frac{-1}{2}}} \, du\\\\ =\int {(u^{\frac{1}{2}}-u^{\frac{-1}{2}})} \, du[/tex]