Given g(x) = x² - 6x - 16, which statement is true?

The correct choice of this question with the given polynomial is "The zeros are -2 and 8, because the factors of g are (x + 2) and (x - 8)". (Correct choice: H)
In this case we have a second order polynomial of the form x² - (r₁ + r₂) · x + r₁ · r₂, whose solution is (x - r₁) · (x - r₂) and where r₁ and r₂ are the roots of the polynomial, which can be real or complex numbers but never both according the fundamental theorem of algebra.
If we know that g(x) = x² - 6 · x - 16, then the factored form of the expression is g(x) = (x - 8) · (x + 2). Hence, the correct choice of this question with the given polynomial is "The zeros are -2 and 8, because the factors of g are (x + 2) and (x - 8)". [tex]\blacksquare[/tex]
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