At 8 a.m. Anne left Austin and headed south at 20 mph. At 10 a.m. Gene left from the same place and headed south on the same road. If Anne was 10 miles ahead by 4 p.m. on the same day, what was Gene's speed in mph

Respuesta :

Using proportions, it is found that Gene's speed was of 25 miles per hour, as he was 30 miles faster over a period of 6 hours.

What is a proportion?

A proportion is a fraction of a total amount.

At 8 a.m. Anne left Austin and headed south at 20 mph, hence when Gene left at 10 a.m., she was 40 mph ahead.

At 4 p.m., that is, 6 hours after Gene left, the distance was of 10 miles, that is, Gene was 30 miles faster in 6 hours, so the difference in the speeds is given by:

d = 30/6 = 5 mph.

Since Anne's speed is of 20 mph, Gene's is given by:

v = 20 + 5 = 25 mph.

More can be learned about proportions at https://brainly.com/question/24372153

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