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After an annual checkup, you leave your physician’s office, where you weighed 683 n. you then get into an elevator that, conveniently, has a scale. find the magnitude and direction of the elevator’s acceleration if the scale reads (a) 725 n and (b) 595 n.

Respuesta :

The magnitude and direction of the elevator’s acceleration for the scale readings are; 0.6033 m/s² upwards and -1.264 m/s² downwards

What is the magnitude of acceleration?

A) We are given;

Weight of man; W = 683 N

Mass is gotten from;

m = W/g

where g is acceleration due to gravity = 9.81 m/s²

m = 683/9.81

m = 69.62 kg

Now, scale reading of lift is w = 725 N. Thus;

Apparent weight = 725 - 683

Apparent weight = 42 N which is  is the force that acts on the body which generates the acceleration.

Thus, acceleration is;

a = 42/69.62

a = 0.6033 m/s² upwards

B) At scale reading of 595 N;

Apparent weight = 595 - 683 = -88 N

Acceleration;

a = -88/69.62

a = -1.264 m/s² downwards

Read more about acceleration at; https://brainly.com/question/25748266

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