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To heat the water in the tank from 50°C to 58°C the immersion heater transfers
4032 kJ of energy to the water.
Calculate the mass of water in the tank.
Specific heat capacity of water= 4200 J/kg°C

Respuesta :

Let's see

  • ∆T=58-50=8°C

So

[tex]\\ \rm\Rrightarrow Q=mc\Delta T[/tex]

[tex]\\ \rm\Rrightarrow 4032=4200(8)m[/tex]

[tex]\\ \rm\Rrightarrow 4032/8=4200m[/tex]

[tex]\\ \rm\Rrightarrow 504=4200m[/tex]

[tex]\\ \rm\Rrightarrow m=0.12kg[/tex]

[tex]\\ \rm\Rrightarrow m=120g[/tex]

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