Respuesta :
Answer:
$ 6.31
Step-by-step explanation:
The TOTAL amount in the account in 3 years will be
40 ( 1+.05)^3 = 46.31
subtract the orignal 40 deposit to get the interest =6.31
[tex]~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$40\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &3 \end{cases}[/tex]
[tex]A=40\left(1+\frac{0.05}{1}\right)^{1\cdot 3}\implies A\approx 46.31~\hfill \underset{earned~interest}{\stackrel{46.31~~ - ~~46}{\approx 6.31}}[/tex]
