NO LINKS!! Please help

Answer:
FJ = 32
IJ = 24
FG = 48
Step-by-step explanation:
Getting Started with FG
[tex]\frac{IH}{AB} =\frac{FG}{ED}[/tex]
[tex]\frac{72}{36} =\frac{FG}{24}[/tex]
[tex]\frac{FG}{24} =2[/tex]
[tex]FG=24(2)=48[/tex]
The proportion between polygons is 2:1
[tex]IJ=2CB[/tex]
[tex]IJ=2(12)=24[/tex]
[tex]FJ=2BC=2(16)=32[/tex]
Hope this helps
Answer:
FJ = 32
IJ = 24
FG = 48
Step-by-step explanation:
Given: HGFJI ~ AEDCB
From inspection of the diagram, the corresponding sides are:
HG~AE
FG~DE
FJ~DC
IJ~CB
IH~BA
The only pair of sides that both have side lengths are IH and BA. Therefore, we can use these to figure out the scale factor of dilation.
IH = 72 and BA = 36
⇒ IH/BA= 72/36 = 2
Therefore, HGFJI is an enlargement of AEDCB by a scale factor of 2
If HG = 56
⇒ AE = 56 ÷ 2 = 28
If DE = 24
⇒ FG = 24 × 2 = 48
If DC = 16
⇒ FJ = 16 × 2 = 32
If CB = 12
⇒ IJ = 12 × 2 = 24