The percent yield shows the extent to which reactants are converted to products. The percent yield of ammonia is 24.7%
The percent yield is obtained from the theoretical yield and the actual yield. The reaction between hydrogen and Nitrogen is;
3H2 + N2 ---->2NH3
If 1 mole of H2 occupies 22.4 dm^3
x moles occupies 12dm^3
x = 0.54 moles
If 1 mole of NH3 occupies 22.4 dm^3
x moles of ammonia occupies 2 dm^3
x = 0.089 moles
Now;
From the reaction equation;
3 moles of hydrogen yields 2 moles of NH3
0.54 moles of hydrogen will yiled 0.54 moles * 2 moles/3 moles
= 0.36 moles of ammonia
Percent yield = 0.089 moles/0.36 moles * 100 = 24.7%
The percent yield of ammonia is 24.7%
Learn more about percent yiled: https://brainly.com/question/13505381
