The volume of gas occupied by 11 grams of nitrogen dioxide gas at STP is 5.15 L.
Ideal gas equation of any gas will be writen as:
PV = nRT, where
P = standard pressure = 1 atm
V = volume = ?
R = universal gas constant = 0.082 L.atm/K.mol
T = standard temperature = 273K
n is the moles of gas which can be calculated by using below equation as:
n = W/M, where
W = given mass = 11g
M = molar mass = 46 g/mol
n = 11 / 46 = 0.239mol
On putting values on the above equation, we get
V = (0.23)(0.082)(273) / (1) = 5.15 L
Hence required volume of gas is 5.15 L.
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