Respuesta :
Answer:
13 sheep, 19 chicken
Step-by-step explanation:
You can start to solve this problem by assigning variables. First, let's assign the number of sheep there are as [tex]x[/tex] and the number of chickens there are as [tex]y[/tex].
Because each sheep has 4 legs, the number of legs for each sheep would be [tex]4x[/tex]. Similarly, because each chicken has 2 legs, the number of legs for each chicken would be [tex]2y[/tex]. Each animal would have 1 head, so the number of heads would just be [tex]x[/tex] and [tex]y[/tex]. Because the number of legs in total are 90, [tex]4x + 2y=90[/tex]. Because the number of heads in total are 32, [tex]x+y=32.[/tex]
There is now a system of equations with two unknown variables and two equations. There are many ways to solve this, but for me, the easiest would be elimination. First, I would double the second equation, [tex]2x+2y=64[/tex]. Then, I would subtract that from the first equation, eliminating [tex]y[/tex]. [tex]2x=26[/tex]. Solving for x gives 13. We can then plug that value into the second equation, making y be [tex]32-13=19[/tex]. This means that [tex]x=13[/tex] and [tex]y=19[/tex], meaning that there are 13 sheep and 19 chicken.
