Answer:
0.025L of 2M HCl
Explanation:
This is a dilution problem involving the equation
[tex]M_1V_1 = M_2V_2[/tex]
Where M is molarity in grams/liter and V is volume in liters, and 1 and 2 represent initial and final states, respectively.
We know that:
[tex]M_1[/tex] = 2, as 2M HCl is the starting substance
[tex]M_2[/tex] = 0.05, as 0.05M HCl is the desired final substance
[tex]V_2[/tex] = 1, as 1 L is the desired volume of the final substance
Now you can solve for [tex]V_1[/tex].
[tex]2V_1 = 0.05(1)\\V_1 = \frac{0.05}{2} \\V_1 = 0.025[/tex]
Therefore, 0.025L of 2M HCl is needed to make 1 L of 0.05M HCl
