The potential energy of a spring is mathematically given as
P.E= 20 J
What is the potential energy of a spring that is compressed 0.65 m by a 25 kg block if the spring constant is 95 n/m?
Question Parameter(s):
is compressed 0.65 m by a 25 kg block
if the spring constant is 95 n/m
Generally, the equation for the potential energy is mathematically given as
PE = mgh
Therefore
P.E=0.5 kx^2
P.E= 0.5 x 95 x (0.65)^2
P.E= 20 J
In conclusion, The potential energy of a spring
P.E= 20 J
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