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Segment AB has point A located at (6, 5). If the distance from A to B is 5 units, which of the following could be used to calculate the coordinates for point B? 5 = square root of the quantity of x minus 6 all squared plus y minus 5 all squared 5 = square root of the quantity of x minus 5 all squared plus y minus 6 all squared 5 = square root of the quantity of x plus 6 all squared plus y plus 5 all squared 5 = square root of the quantity of x plus 5 all squared plus y plus 6 all squared

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MrRoyal

The distance of segment AB is the number of units on the segment

The equation that can be used to determine the coordinates of point B is [tex]5 = \sqrt{(x -6)^2 + (y - 5)^2}[/tex]

How to determine the equation?

The given parameters are:

  • A = (6,5)
  • AB = 5 units

The distance AB is calculated using:

[tex]AB = \sqrt{(x_2 -x_1)^2 + (y_2 - y_1)^2}[/tex]

This gives

[tex]5 = \sqrt{(x -6)^2 + (y - 5)^2}[/tex]

Hence, the equation that can be used to determine the coordinates of point B is [tex]5 = \sqrt{(x -6)^2 + (y - 5)^2}[/tex]

Read more about distance equations at:

https://brainly.com/question/7243416

heathermalatesta

Answer:

√(x-6)² + (y-5)²

Step-by-step explanation:

The Distance Formula is √(x2 - x1)² + (y2 - y1)²

If you plug in the known values, you get √(x - 6)² + (y - 5)²

This is our answer.

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