The equilibrium pressure for the sulfur dioxide in the reaction has been 0.0843 bar.
The equilibrium is the condition in which the partial pressure of the product and the reactant molecules is equal.
The ICE table for the partial pressure is attached.
Based on the pressure of equilibrium, the pressure constant is given as:
[tex]k_p=\rm \dfrac{[pNO]\;[pSO_2]}{[pNO][pSO_3]}\\0.0118=\dfrac{a^2}{(0.86-a)^2}\\a=0.0843[/tex]
Thus, the partial pressure of sulfur dioxide at equilibrium is 0.0843 bar.
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