Answer:
3(x+2)/(2(x+4))
Step-by-step explanation:
A compound fraction is simplified by rewriting it as a simple fraction, and reducing it to lowest terms by cancelling common factors from numerator and denominator. The division of one fraction by another is accomplished in the usual way: multiply the numerator by the inverse of the denominator.
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[tex]\dfrac{\left(\dfrac{6x^2-24}{x^2+7x+12}\right)}{\left(\dfrac{4x^2-4x-8}{x^2+4x+3}\right)}=\left(\dfrac{6x^2-24}{x^2+7x+12}\right)\times\left(\dfrac{x^2+4x+3}{4x^2-4x-8}\right)\\\\=\dfrac{6(x-2)(x+2)}{(x+3)(x+4)}\times\dfrac{(x+1)(x+3)}{4(x-2)(x+1)}=\dfrac{3(x-2)(x+1)(x+2)(x+3)}{2(x-2)(x+1)(x+3)(x+4)}\\\\=\boxed{\dfrac{3(x+2)}{2(x+4)}}[/tex]
