Which expression is equivalent to startfraction 5 y cubed over (5 y) superscript negative 2 baseline endfraction?

Respuesta :

The expression that is equivalent to the given expression is 125y⁵.

The given expression is:

[tex]\frac{5y^{3} }{(5y)^{-2} }[/tex]

What are some important power rules applicable to the given problem?

Some important power rules applicable to this problem are:

1)[tex](ab)^m=a^mb^m[/tex]

2)[tex]\frac{1}{a^{-n} } =a^n[/tex]

So, [tex]\frac{5y^{3} }{(5y)^{-2} } =\frac{5y^{3} }{5^{-2} y^{-2} }[/tex].....by power rule (1)

[tex]=(\frac{5}{5^{-2} } )(\frac{y^3}{y^{-2} })[/tex]

[tex]=5^3y^5[/tex].....by power rule(2)

[tex]=125y^5[/tex]

Hence, the expression that is equivalent to the given expression is 125y⁵.

To get more about power rules visit:

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